Holooly Plus Logo

Question 6.IT.9: An aldehyde (A) (C11H10O) which does not undergo self aldol ......

An aldehyde (A) (C_{11}H_{10}O) which does not undergo self aldol condensation, gives benzaldehyde and 2 moles of (B) on ozonolysis. Compound (B) on oxidation with Tollen’s reagent gives an oxalic acid. Calculate the number of \pi -bonds in the original C_5H_{12}O

The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.

As per given problem the structure of C_{11}H_{10} is

\begin{matrix} CH = CH – CH = CH – CHO \\\overset{\text {Heat}}{\underset{- H _2 O / Zn}{\longrightarrow }} \\\\\\\\\ \end{matrix}

\begin{matrix} \overset {\text {(A)}}{} \stackrel{ +2( CHO )_2}{\text {(B)}} & \overset{Ag \left( NO _3\right)_2^{+}}{\xrightarrow {\hspace{2 cm}} }  & \stackrel{ (COOH)_2}{\text {Oxalic acid}}\\\\\\\\\\\ \end{matrix}

Related Answered Questions

Question: 6.MCQ.161

Verified Answer:

Question: 6.MCQ.156

Verified Answer:

Question: 6.MCQ.7

Verified Answer:

(d) \stackrel{+\delta}{ C } H _2= CH -\sta...
Question: 6.SSE.31

Verified Answer:

\begin{matrix} \overset{KCN}{\underset{DM}...
Question: 6.SSE.7

Verified Answer:

\begin{matrix} \overset{K_2Cr_2O_7}{\under...
Question: 6.IT.2

Verified Answer:

CH _3 CH _2 CH ( OH ) CH _2 CHO