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Question 6.MCQ.7: Polarization of acrolein as (a) CH2 = CH - CHO (b) CH2 = CH ......

Polarization of acrolein as

(a) \stackrel{+\delta}{ C } H _2= CH -\stackrel{-\delta}{ C } HO

(b) \stackrel{-\delta}{ C } H _2= CH -\stackrel{+\delta}{ C } HO

(c) \stackrel{-\delta}{ C}H _2= CH -\stackrel{+\delta}{ C } HOc

(d) \stackrel{+\delta}{ C } H _2= CH -\stackrel{-\delta}{ C } HO

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(d) \stackrel{+\delta}{ C } H _2= CH -\stackrel{-\delta}{ C } HO

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