Identify (X), (Y) and (Z) in the following synthetic scheme and write their structures. Explain the formation of labeled formaldehyde (H_2C^*O) as one of the products when compound (Z) is treated with HBr and subsequently ozonolysed. Mark the C^* carbon in the entire scheme.
BaC ^* O _3+ H _2 SO _4 \rightarrow( X ) \text { gas }(Here C^* denotes C^{14} )
CH_2 = CH – Br \overset{\text { (i) } Mg \text { / ether, (ii) X (iii) } H _3 O}{\xrightarrow {\hspace{2 cm}} } (Y) \overset{LiAlH_4}{\xrightarrow {\hspace{2 cm}} } (Z)[IIT, 2001]
CH_2 = CHBr \overset{\text { (i) } Mg / \text { ether }}{\xrightarrow {\hspace{2 cm}} } CH_2 = CHMgBr \overset{\text { (ii) } C ^* O _2( X )}{\underset{\text { (iii) } H _3 O ^{-}}{\xrightarrow {\hspace{2 cm}} }} CH_2 = CHC^*OOH \overset{LiAlH_4}{\xrightarrow {\hspace{2 cm}} }
(Y)
Formation of C ^* H _2 O from (Z)
CH _2= CH \cdot C ^* H _2 OH \overset{ H ^{-}}{\longrightarrow} CH _2= CH _{+} \cdot C ^* H _2 \longleftrightarrow \\ C ^{+} H _2- CH = C ^* H _2 \quad \stackrel{ Br }{\longrightarrow} BrCH _2 \cdot CH = C ^* H _2 \stackrel{ O _3}{\longrightarrow} C ^* H _2= O