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Question 3.95: Assume 100 grams of mixture. This means the mass of each com......

Assume 100 grams of mixture. This means the mass of each compound, in grams, is the same as its percentage. Find the mass of C from CO and from \text{CO}_2 and add these masses together.

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100\text{ g of mixture}=35\text{ g CO and 65 g CO}_2. \\ \text{C from CO}=(35.0\text{ g CO})\left\lgroup\frac{1\text{ mol CO}}{28.01\text{ g CO}} \right\rgroup \left\lgroup\frac{1\text{ mol C}}{1\text{ mol CO}} \right\rgroup \left\lgroup\frac{12.01\text{ g C}}{1\text{ mol C}} \right\rgroup =15.007\text{ g C (unrounded)} \\ \text{C from CO}_2=(65.0\text{ g CO}_2)\left\lgroup\frac{1\text{ mol CO}_2}{44.01\text{ g CO}_2} \right\rgroup \left\lgroup\frac{1\text{ mol C}}{1\text{ mol CO}_2} \right\rgroup \left\lgroup\frac{12.01\text{ g C}}{1\text{ mol C}} \right\rgroup =17.738\text{ g C (unrounded)} \\ \text{Mass percent C}=\left\lgroup\frac{(15.007+17.738)\text{g}}{100\text{ g Sample}} \right\rgroup \times 100\%=32.745=32.7\%\text{ C}

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