Question 3.76: The moles of narceine and the moles of water are required. W......
The moles of narceine and the moles of water are required. We can assume any mass of narceine hydrate (we will use 100 g), and use this mass to determine the mass of water present and convert the mass to moles of the hydrate. The mass of water will be converted to moles. Finally, the ratio of the moles of hydrate to moles of water will give the amount of water present.
Step-by-Step
\text{Moles narceine hydrate}=(100\text{ g narceine hydrate})\left\lgroup\frac{\text{1 mol narceine hydrate}}{499.52\text{ g narceine hydrate}} \right\rgroup \\ =0.20019\text{ mol narceine hydrate} \\ \text{Moles H}_2\text{O}=(100\text{ g narceine hydrate})\left\lgroup\frac{\text{10.8\% H}_2\text{O}}{100\%\text{ narceine hydrate}} \right\rgroup\left\lgroup\frac{1\text{ mol H}_2\text{O}}{18.02\text{ g H}_2\text{O}} \right\rgroup \\ =0.59933\text{ mol H}_2\text{O}
The ratio of water to hydrate is : (0.59933 mol) / (0.20019 mol) = 3
Thus, there are three water molecules per mole of hydrate. The formula for narceine hydrate is narceine\cdot 3\text{H}_2\text{O}
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