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Question 8.2: Consider a QAM (Quadrature Amplitude Modulation) constellati......

Consider a QAM (Quadrature Amplitude Modulation) constellation of N = M² signals, M even, regularly deployed on a X Y Cartesian grid. Any point of the constellation has amplitude i−1/2  and j − 1/2 along the X or Y axis, respectively, where −M/2 + 1 < i < M/2 and −M/2 + 1 < j < M/2 are integer numbers. Evaluate the PAPR for such a signal.

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First of all, notice that a scale factor common to all constellation points has no influence on the PAPR or the crest factor. The RMS signal value is defined as:

\begin{aligned} \text{RMS}^2 & =\frac{1}{N} \cdot 4 \cdot \sum_{i=1}^{M / 2} \sum_{j=1}^{M / 2}\left[\left(i-\frac{1}{2}\right)^2+\left(j-\frac{1}{2}\right)^2\right] \\ & =\frac{1}{N} \cdot 4 \cdot\left[\frac{M}{2} \sum_{i=1}^{M / 2}\left(i-\frac{1}{2}\right)^2+\frac{M}{2} \sum_{j=1}^{M / 2}\left(j-\frac{1}{2}\right)^2\right] \\ & =\frac{1}{M^2} \cdot 4 \cdot 2 \cdot \frac{M}{2} \sum_{k=1}^{M / 2}\left(k-\frac{1}{2}\right)^2=\frac{1}{M^2} \cdot 4 \cdot 2 \cdot \frac{M}{2} \cdot \frac{M}{24} \cdot\left(M^2-1\right), \end{aligned}

where the factor 1/N² normalizes the power of the symbols, assumed here equiprobable, while the factor 4 accounts for the number of quadrants. We thus have:

\text{RMS}^2=\frac{M^2-1}{6}=\frac{N-1}{6} .

The peak value is:

\text { PEAK }=\sqrt{2} \cdot\left(\frac{M}{2}-\frac{1}{2}\right)=\frac{M-1}{\sqrt{2}} .

The crest factor C_F in term of RMS value is therefore:

C_F=\frac{ \text{PEAK} }{ \text{RMS} }=\sqrt{\frac{6}{M^2-1}} \frac{M-1}{\sqrt{2}}=\sqrt{3} \sqrt{\frac{M-1}{M+1}}=\sqrt{3} \frac{\sqrt{N}-1}{\sqrt{N-1}} .

For example we have: 4QAM, N=4 \rightarrow C_F=1,0\text{ dB} (trivial since the four points are on a circle, hence constant power, non-varying envelope, no PAPR); 16QAM, N = 16

\begin{aligned} & \rightarrow C_F=3 / \sqrt{5}, 2.6\text{ dB} ; 64 \text{QAM} , N=64 \rightarrow C_F=\sqrt{7 / 3}, 3.7\text{ dB} ; 1024 \text{QAM}, \\ & N=1024 \rightarrow C_F=31 / \sqrt{341}, 4.5\text{ dB} ; \infty \text{QAM} , N=\infty \rightarrow C_F=\sqrt{3}, 4.8\text{ dB}. \end{aligned}

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