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Question 8.1: Evaluate the PAPR of a single-tone and of a two-tone signal,......

Evaluate the PAPR of a single-tone and of a two-tone signal, assuming that the two tones have the same amplitude.

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In a sinusoidal signal of peak value x_p, the effective value is x_p / \sqrt{2}; since power is proportional to the square of the signal, the ratio between the peak power and the average power, i.e., the PAPR, is 2. For a two-tone signal with peak value y_p and equal tone amplitude, the effective value for each tone is y_p / \sqrt{2} and the total average power of the two tones is 2 y_p^2 / 2=y_p^2. However, for the two-tone signal, the peak value is 2 y_p, leading to a peak power 4 y_p^2. Thus, the peak to average power ratio is 4.

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