CTFT of the convolution of some signals
Find the CTFT of the convolution of 10sin(t)with 2δ(t + 4).
Method 1: Do the convolution first and find the CTFT of the result.
10sin(t)^∗ 2δ(t + 4) = 20sin(t + 4)
Apply the time-shifting property.
20sin(t + 4) \overset{\mathcal{F}}{\longleftrightarrow } j20π [δ (ω + 1) − δ( ω− 1)]e^{j4ω}or
20sin(t + 4)\overset{\mathcal{F}}{\longleftrightarrow } j10[δ ( f + 1/2π ) − δ( f − 1/2π )]e^{j8π f}Method 2: Do the CTFT first to avoid the convolution.
10sin(t)^∗ 2δ(t + 4)\overset{\mathcal{F}}{\longleftrightarrow }\mathcal{F}(10sin(t))\mathcal{F}(2δ(t + 4)) = 2{\mathcal{F}}(10sin(t))\mathcal{F}(δ(t))e^{j4ω} 10sin(t)^∗ 2δ(t + 4)\overset{\mathcal{F}}{\longleftrightarrow }j20π[δ(ω+1)-δ(ω-1)e^{j4ω}or
10sin(t)^∗ 2δ(t + 4)\overset{\mathcal{F}}{\longleftrightarrow }\mathcal{F}(10sin(t)){\mathcal{F}}(2δ(t + 4)) = 2\mathcal{F}(10sin(t))\mathcal{F}(δ(t))e^{j8πf}10sin(t) ^∗ 2δ(t + 4)\overset{\mathcal{F}}{\longleftrightarrow }j10[δ ( f + 1/2π ) − δ( f − 1/2π )]e^{j8π f}.