Derive the singular ideal MHD equilibrium, which is formed under the dipole-type deformation of the magnetic field with the neutral X-point (see Problem 4.3.6).
The respective solution containing the current sheet (as shown in Figure 4.13(d)) can be constructed in the following way. Any potential planar magnetic field [B_{x}(x, y),B_{y}(x, y)] can be represented as B_{x} − iB_{y} = f(z) = u(x, y) + iv(x, y), where f(z) is an analytical function of the complex variable z = x + iy. Indeed, the divergence-free and curl-free requirements for \vec{B} , namely \frac{∂B_{x}}{∂x} = − \frac{∂B_{y}}{∂y} and \frac{∂B_{x}}{∂y} = \frac{∂B_{y}}{∂x} , are equivalent to the Cauchy-Riemann equations for the real and imaginary parts of f(z): \frac{∂u}{∂x} = \frac{∂v}{∂y} , \frac{∂v}{∂x} = − \frac{∂u}{∂y} . For example, the initial field, specified by the flux function (4.77), corresponds to f(z) = iB_{0}z/R. Then, the deformed magnetic field with the current sheet shown in Figure 4.13(d) can be described as
ψ_0(r,θ)=\frac{B_0r^2}{2R}\cos 2θ (4.77)
B_{x} − iB_{y} = \frac{iB_{0}}{R} (z − ia)^{1/2}(z − ib)^{1/2}, (4.83)
where the current sheet corresponds to the branch cut in the complex plane between z = ia and z = ib, where two neutral Y -points are formed. In order to find the values of a and b, consider the magnetic field of Equation (4.83) far enough from the current sheet, i.e., for |z| ≫ a, b. Thus,
B_{x} − iB_{y} = \frac{iB_{0}}{R} z \left(1 − \frac{ia}{z} \right)^{1/2} \left( 1 − \frac{ib }{z}\right)^{1/2} ≈ \frac{iB_{0}}{R} z + \frac{B_{0}}{2R} (a + b),
which means that this current sheet generates there an additional uniform magnetic field B_{x} = B_{0}(a + b)/2R. Therefore, in order to comply with the dipole contribution to the boundary flux perturbation, this extra field should be equal to B_{1x} = B_{0}δ_{0}/2R, i.e., (a + b) = δ_{0}. In other words, the current sheet is centered at y = y_{1} = δ_{0}/2, the location of the X-point of the regular solution of Figure 4.13(c). Then, if ε is a half-length of the current sheet, i.e., a = δ_{0}/2 − \epsilon, b = δ_{0}/2 + \epsilon, one can re-write (4.83) as
B_{x} − iB_{y} = \frac{iB_{0}}{R} \left[ z − i \left(\frac{δ_{0}}{2} − \epsilon \right) \right]^{1/2} \left[ z − i \left(\frac{δ_{0}}{2} + \epsilon \right) \right]^{1/2} (4.84)
Another requirement applied to this singular solution, which allows to derive \epsilon, is that all separatrix lines and, therefore, the current sheet from which they originate should correspond to ψ = ψ_{s} = 0. This ensures that the separatrix lines end up at the boundary r = R at the points (S^{′}_{1}, S^{′}_{2}, S^{′}_{3}, S^{′}_{4}), preserving in this way the field lines’ connectivity of the initial magnetic field (see Figure 4.13(d)). Thus, consider magnetic field (4.84) on the horizontal line y = δ_{0}/2, which stretches from the center of the current sheet to the point A at the boundary circle as shown in Figure 4.13(d). It follows from expression (4.84) that along this line, where z = x + iδ_{0}/2, B_{y}(x) = − \frac{B_{0}}{R} (x^{2} + \epsilon^{2})^{1/2}, hence
ψ_{A} − ψ_{s} = − \int_{0}^{x_{A}} B_{y}dx = \frac{B_{0}}{R} \int_{0}^{x_{A}} (x^{2} + \epsilon^{2})^{1/2}dx =
ψ^{(R)}(θ_{A}) = ψ^{(R)}_{0} (θ_{A}) + ψ^{(R)}_{1} (θ_{A}) ≈ \frac{B_{0}R}{2}, (4.85)
where x_{A} = (R^{2}−δ^{2}_{0}/4)^{1/2}. A straightforward derivation of the integral in (4.85) yields
\int_{0}^{x_{A}} (x^{2} + \epsilon^{2})^{1/2} dx ≈ \frac{1}{2} [R^{2} − \frac{δ^{2}_{0}}{4} + \epsilon^{2} sinh^{−1}(R/\epsilon)],
which being inserted into equation (4.85) results in
\epsilon ≈ \frac{δ_{0}}{2\mathcal{L}^{1/2}}, (4.86)
where \mathcal{L} = \ln(R/δ_{0}) ≫ 1.
Thus, two different magnetostatic equilibria are associated with the dipoletype deformation of the initial X-point magnetic configuration (4.77). There is the regular equilibrium shown in Figure 4.13(c), and the singular current sheet equilibrium of Figure 4.13(d). The latter corresponds to a perfectly conducting fluid, where connectivity of the magnetic field-line footpoints is preserved. However, presence of a very small but finite resistivity leads to magnetic reconnection, which eliminates the magnetic field singularity (the current sheet), and enables transition to the regular equilibrium with a lower magnetic energy.
Therefore, this process is similar to forced magnetic reconnection discussed in Problems 4.3.1 and 4.3.2.