Determine the reduction in the annual energy costs due to staggered duty
cycling of three identical fan motors (each rated at 30 \ kW 40 \ HP). The motor manufacturer specifies that a cycle has 20 \ min on and 10 \ min off as the minimum duty cycle. The utility monthly demand charge is $10/kW. First, determine the recommended NEMA duty period assuming 2-pole motors.
(a) Using Table 10.2, the allowable number of starts per hour for 40 \ HP, two-pole motors is 3.7 \ starts/h. Thus, each start should last as in the following:
Start period=\frac{60 \ min/h}{3.7 \ stars/h}=14.4 \ min/star
The duty period is thus about 15 \ min. Since the duty period is the sum of the off time and the on time and since the minimum off time is about 2 min (130 s based on Table 10.2), the maximum on time allowed by NEMA standard is 13 \ min.
Thus, the manufacturer’s on time is longer than that recommended by NEMA.
(b) The reduction in the electrical demand peak due to staggered duty cycling approach is 1/3 of the total demand of all the three motors (or 1/3 ∗ 90 kW = 30 \ kW). Indeed, at any given time, only two out of the three motors are operating. Thus, the annual savings in electrical demands charges are given as follows:
\Delta kW=12*30 \ kW=360 \ kW/yearTherefore, the staggered duty cycling control provides an annual energy cost savings of \$3600.
TABLE 10.2
Allowable Number of Starts Per Hour and Minimum Off Time for Motor Loads
Six-Pole Motors | Four-Pole Motors | Two-Pole Motors | Motor Size HP (kW) |
|||
Min. Off Time (s) | Max. Starts/h | Min. Off Time (s) | Max. Starts/h | Min. Off Time (s) | Max. Starts/h | |
35 | 26.1 | 39 | 23.0 | 77 | 11.5 | 2.0 (1.5) |
37 | 18.4 | 42 | 16.3 | 83 | 8.1 | 5.0 (3.75) |
39 | 15.8 | 44 | 13.9 | 88 | 7 | 7.5 |
44 | 12.1 | 50 | 10.7 | 100 | 5.4 | 15 |
48 | 10.9 | 55 | 9.6 | 110 | 4.8 | 20.0 (15.0) |
51 | 10.0 | 58 | 8.8 | 115 | 4.4 | 25.0 (18.75) |
53 | 9.3 | 60 | 8.2 | 120 | 4.1 | 30.0 (22.5) |
57 | 8.4 | 65 | 7.4 | 130 | 3.7 | 40.0 (30.0) |
64 | 7.7 | 72 | 6.8 | 145 | 3.4 | 50 |