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Question 8.2.2: Draw the Lewis structure for a. SCl2 b. CN^−...

Draw the Lewis structure for
a.  SCl_{2}
b. CN^{−}

Step-by-Step
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You are asked to draw the Lewis structure for a molecule or ion.
You are given the chemical formula for a molecule or ion.
a. Step 1: 6 + (2 × 7) = 20 valence electrons (or 10 pairs)
Steps 2 and 3:

Cl — S — Cl

Sulfur has a lower affinity for electrons than Cl, so it is the central atom.
Steps 4 and 5:

:\overset{..}{\underset{..}{Cl}}- \overset{..}{\underset{..}{S}}- \overset{..}{\underset{..}{Cl}} :

All atoms have an octet of electrons, so it is not necessary to create multiple bonds.
b. Step 1: 4 + 5 + 1 = 10 valence electrons (or 5 pairs)
Steps 2 and 3:

C — N

Step 4:

\overset{..}{\underset{..}{C}}- \overset{..}{\underset{..}{N}}

Step 5:

\left[:C\equiv N:\right]^{-}

A triple bond between carbon and nitrogen results in a satisfied octet for both atoms.
Is your answer reasonable? As a final check, always count the number of valence electrons in your Lewis structure and confirm that it matches the number of valence electrons from Step 1.

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