Draw the Lewis structures for carbon dioxide, CO_{2}.
Table 1
STEP 1 Determine the arrangement of atoms. In CO_{2}, the central atom is C because there is only one C atom.
O C O
STEP 2 Determine the total number of valence electrons. We use the group number to determine the number of valence electrons for each of the atoms in the molecule.
Table 2
STEP 3 Attach each bonded atom to the central atom with a pair of electrons.
O\mathrm{:}C\mathrm{:}O or O \space — \space C \space — \space O
We use four valence electrons to attach the central C atom to two O atoms, which leaves 12 valence electrons.
STEP 4 Use the remaining electrons to complete octets, using multiple bonds if needed.
The 12 remaining electrons are placed as six lone pairs of electrons on the outside O atoms. However, this does not complete the octet of the C atom.
\mathrm {:}\overset{\mathrm {.~.}}{\underset{.~.}{O}} \mathrm {:}C\mathrm {:}\overset{\mathrm {.~.}}{\underset{.~.}{O}} \mathrm {:} or \mathrm {:}\overset{\mathrm {.~.}}{\underset{.~.}{O}} \space — \space C \space — \space \overset{\mathrm {.~.}}{\underset{.~.}{O}} \mathrm {:}
To obtain an octet, the C atom must share pairs of electrons from each of the O atoms. When two bonding pairs occur between atoms, it is known as a double bond.
Table 1 :
ANALYZE THE PROBLEM | Given | Need | Connect |
CO_{2} | Lewis structure | total valence electrons |
Table 2 :
Element | Group | Atoms | Valence Electrons | Total |
C | 4A (14) | 1 C × | 4 \space e^{-} = | 4 \space e^{-} |
O | 6A (16) | 2 O × | 6 \space e^{-} = | 12 \space e^{-} |
Total valence electrons for CO_{2}= | 16 \space e^{-} |