Question 6.CC.6: Use electronegativity values to classify the bond between ea......
Use electronegativity values to classify the bond between each of the following pairs of atoms as nonpolar covalent, polar covalent, or ionic:
a. Sr and Cl b. C and S c. O and Br
Step-by-Step
a. An electronegativity difference of 2.0 (Cl 3.0 – Sr 1.0) makes this an ionic bond.
b. An electronegativity difference of 0.0 (C 2.5 – S 2.5) makes this a nonpolar covalent bond.
c. An electronegativity difference of 0.7 (O 3.5 – Br 2.8) makes this a polar covalent bond.
Related Answered Questions
Question: 6.CC.9
Verified Answer:
a. HF molecules, which are polar with H bonded to ...
Question: 6.CC.8
Verified Answer:
From its Lewis structure, we see that AsCl_...
Question: 6.CC.7
Verified Answer:
From its Lewis structure, we see that AsCl_...
Question: 6.CC.5
Verified Answer:
The central atom is C.
S C S
Determine the total n...
Question: 6.CC.4
Verified Answer:
Two nonmetals share electrons and form a molecular...
Question: 6.CC.3
Verified Answer:
This compound contains the SO_4^{2-}[/latex...
Question: 6.CC.2
Verified Answer:
Magnesium phosphide is an ionic compound that cont...
Question: 6.CC.1
Verified Answer:
a. Br atoms gain one electron to achieve a stable ...
Question: 6.14
Verified Answer:
Table 1
STEP 1 Determine the arrangement of atom...
Question: 6.13
Verified Answer:
STEP 1 Determine the arrangement of atoms. For t...