Question 19.7: Electronic Polarization in Copper Suppose that the average d......
Electronic Polarization in Copper
Suppose that the average displacement of the electrons relative to the nucleus in a copper atom is 10^{-8} Å when an electric field is imposed on a copper plate. Calculate the electronic polarization.
Step-by-Step
The atomic number of copper is 29, so there are 29 electrons in each copper atom. The lattice parameter of copper is 3.6151 Å. Thus,
z = \frac{(4 \ \text{atoms}/\text{cell})(29 \ \text{electrons/atom})}{(3.6151 × 10^{-10} m)^3/\text{cell}} = 2.455 × 10^{30} \text{electrons}/m^3
P = zqd = (12.455 × 10^{30} \ \frac{\text{electrons}}{m^3}) (1.6 × 10^{-19} \ \frac{C}{\text{electron}})(10^{-8} Å)(10^{-10} \ m /Å)
= 3.93 × 10^{-7} C/m^2
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