Find possible inflection points for f(x)=x^{6}-10x^{4}.
In this case f^{\prime}(x)=6x^{5}-40x^{3}{\mathrm{~and}}
f^{\prime\prime}(x)=30x^{4}-120x^{2}=30x^{2}(x^{2}-4)=30x^{2}(x-2)(x+2)A sign diagram for f^{\prime\prime} is as follows:
Figure (1)
From the sign diagram we see that f^{\prime\prime} changes sign at x = −2 and at x = 2, so these are inflection points. Since f^{\prime\prime} does not change sign at x = 0, it is not an inflection point, even though f^{\prime\prime}(0) = 0.