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Question 8.2.1: Measured in milligrams per litre, the concentration of a dru......

Measured in milligrams per litre, the concentration of a drug in the bloodstream, t hours after injection, is given by the formula

c(t)={\frac{t}{t^{2}+4}},\;t\geq0

Find the time of maximum concentration.

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Differentiating with respect to t yields

c^{\prime}(t)={\frac{1\cdot(t^{2}+4)-t\cdot2t}{(t^{2}+4)^{2}}}={\frac{4-t^{2}}{(t^{2}+4)^{2}}}={\frac{(2+t)(2-t)}{(t^{2}+4)^{2}}}

For t ≥ 0, the term 2 − t alone determines the sign of the fraction, because the other terms are positive: if t ≤ 2, then c^{\prime}(t) ≥ 0; whereas if t ≥ 2, then c^{\prime}(t) ≤ 0.We conclude that t = 2 maximizes c(t). Thus, the concentration of the drug is highest two hours after injection. Because c(2) = 0.25, the maximum concentration is 0.25 mg.

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