Show that the function f (x) = x^{4} does not have an inflection point at x = 0, even though f^{\prime \prime}(0) = 0.
Here f^{\prime }(x) = 4x^{3} and f^{\prime \prime}(x) = 12x^{2}, so that f^{\prime \prime} (0) = 0. But f^{\prime \prime}(x) > 0 for all x\neq 0, and so f^{\prime \prime} does not change sign at x = 0. Hence, x = 0 is not an inflection point—in fact, it is a global minimum, as shown in Fig. 8.6.3.