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Question 18.p.4: Identify the conjugate pairs by first identifying the specie......

Identify the conjugate pairs by first identifying the species that donates \text{H}^+ (the acid) in either reaction direction. The other reactant accepts the \text{H}^+ and is the base. The acid has one more H and +1 greater charge than its conjugate base.

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a) \text{CH}_3\text{COOH has one more H}^+\text{ than CH}_3\text{COO}^-. \text{H}_3\text{O}^+\text{ has one more H}^+\text{ than H}_2\text{O}. \text{Therefore, CH}_3\text{COOH and H}_3\text{O}^+  \text{ are the acids, and CH}_3\text{COO}^-\text{ and H}_2\text{O} are the bases. The conjugate acid/base pairs are \text{CH}_3\text{COOH/CH}_3\text{COO}^-\text{ and H}_3\text{O}^+/\text{H}_2\text{O}.
b) \text{H}_2\text{O donates a H}^+\text{ and acts as the acid. F}^-\text{ accepts the H}^+ and acts as the base. In the reverse direction, HF acts as the acid and \text{OH}^- acts as the base. The conjugate acid/base pairs are \text{H}_2\text{O/OH}^-\text{ and HF/F}^ –.

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