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Question 11.7: Maximum Load Transmitted by a Gear Based on Wear Strength an......

Maximum Load Transmitted by a Gear Based on Wear Strength and Using the Buckingham Formula

The pinion of Example 11.6 is to be mated with a gear. Determine:

a. The allowable load for wear for the gear set using the Buckingham formula.

b. The maximum load that can be transmitted.

Given: N_p =25, d_p =50 mm, b =45 mm, N_g =60.

Design Decision: The mating gear is made of 60-tooth cast iron.

Step-by-Step
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a. Using Equation (11.40),

Q=\frac{2 N_g}{N_p+N_g}     (11.40)

Q=\frac{2 N_g}{N_p+N_g}=\frac{120}{85}=\frac{24}{17}

By Table 11.9, K =1. 014 MPa for 200 Bhn. Applying Equation (11.38),

F_w=d_p b Q K      (11.38)

F_w=d_p b Q K=(50)(45)\left(\frac{24}{17}\right)(1.014)=3.221  kN

b. The dynamic load, from Example 11.6, is 1.77 F_t . The wear-limiting value of the transmitted load, using Equation (11.41), is then

F_w \geq F_d      (11.41)

3.221=1.77  F_t \quad \text { or } \quad F_t=1.82  kN

TABLE 11.9
Surface Endurance Limit S_e and Wear Load Factor K for Use in the Buckingham Equation
K
Materials in Pinion and Gear S_e \phi=20^{\circ} \Phi=25^{\circ}
Both steel gears, with average 50 (345) 41 (0.283) 51 (0.352)
Bhn of pinion and gear
150
200 70 (483) 79 (0.545) 98 (0.676)
250 90 (621) 131 (0.903) 162 (1.117)
300 110 (758) 196 (1.352) 242 (1.669)
350 130 (896) 270 (1.862) 333 (2.297)
400 150 (1034) 366 (2.524) 453 (3.124)
Steel (150 Bhn) and cast iron 50 (354) 60 (0.414) 74 (0.510)
Steel (200 Bhn) and cast iron 70 (483) 119 (0.821) 147 (1.014)
Steel (250 Bhn) and cast iron 90 (621) 196 (1.352) 242 (1.669)
Steel (150 Bhn) and phosphor bronze 59 (407) 62 (0.428) 77 (0.531)
Steel (200 Bhn) and phosphor bronze 65 (448) 100 (0.690) 123 (0.848)
Steel (250 Bhn) and phosphor bronze 85 (586) 184 (1.269) 228 (1.572)
Cast iron and cast iron 90 (621) 264 (1.821) 327 (2.555)
Cast iron and phosphor bronze 83 (572) 234 (1.614) 288 (1.986)

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