Predict the number of signals and multiplicity of the respective signals in the following compounds.
(i) CH3CH3 (ii) Cl—CH2—CH2—CH2—Cl
(iii) CH2∣ CH2——O∣CH2
(iv)CH3╲╱CH3CH—C≡N
(v)CH3—C∣ClCH2
(i) One signal Singlet as all hydrogens are equivalent
(ii) Cl—CH2a—CH2b—CH2a—Cl
2- signals; signal of CH2 (b) appears as a quintet (5 peaks n +1 rule; 4 + 1 = 5 and that of CH2 (a) protons as a triplet (n+1 rule; 2 + 1=3)
(iii) aCH2∣ bCH2——O∣aCH2
2–signals A four proton triplet and a two proton quintet (5 peaks)
(iv)CH3b╲╱CH3bCaH—C≡N
2– signals A six proton doublet and a one proton septet
(v) CH3c╲ ╱Cl CC Ha╱ ╲bH
3– signals Ha and Hb cause splitting of signals and each appears as a doublet. CH3 appears as a singlet.