The dielectric slab waveguide shown in Fig. 8.20 is infinite in extent in the x– and y-directions, having refractive indices n_{1} \gt n_{2} . Find the maximum angle of incidence \theta_{m} for total internal reflection at the interface between the core and cladding.
Applying Snell’s law to the entrance surface, we have
n_{o} \sin \theta _{m} = n_{1} \sin (90^{\circ } – \theta _{c}) \\ \quad \quad \quad \quad = n_{1} \cos \theta _{c}The critical angle at the interface between the core and cladding is
\sin \theta _{c} = n_{2} / n_{1}Combining the two equations, we have
n_{o} \sin \theta _{m} = n_{1} \sqrt{1 – (n_{2} / n_{1})^{2}}The maximum angle of incidence is therefore
\theta _{m} = \sin ^{ – 1} \left[ \frac{1}{n_{o}} \sqrt{ n^{2}_{1} – n^{2}_{2}}\right]The wave incident at an angle less than \theta_{m} is guided through the dielectric slab by successive total internal reflections at the interface between the core and cladding.