A transformer with a 1 : 6 turns ratio has 720 V across 7200 \Omega in the secondary. (a) How much is I_S? (b) Calculate the value of I_P.
Question 18.13: A transformer with a 1:6 turns ratio has 720 V across 7200 Ω...
a. I_S=\frac{V_S}{R_L}=\frac{720 V}{7200\Omega}
=0.1 A
b. With a turns ratio of 1 : 6, the current ratio is 6 : 1. Therefore,
I_P=6\times I_S=6\times 0.1
=0.6 A
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