Estimate the symmetrical short-circuit current at the secondary side of a
13.8 kV−208Y/120−V transformer rated at 1000 kVA with Z = 5% and supplied by a utility having 15 kVA fault current capabilities.
First, the MVASC values for both the utility and the transformer are estimated. For the utility (using the utility distribution voltage and the utility fault current),
MVASC,U=3∗13.8 kV∗15 kVA=358.52 MVAFor the transformer using Equations 8.13 and 8.14,
Y=Z(%)100 (8.13)
MVASC=YMVA (8.14)
MVASC,T=0.051000 kVA=20 MVASince the utility source and the transformer are in series, the total MVASC−tot value can be estimated using Equation 8.16:
1/MVASC−tot=1/MVASC,1+1/MVASC,2+…+1/MVASC,n (8.16)
1/MVASC−tot=1/MVASC,U+1/MVASC,T=358.521+201=0.05279Thus,
1/MVASC−tot=0.052791=18.94 MVATherefore, the symmetrical short-circuit current at the secondary side of the transformer can be calculated using Equation 8.17 with a line voltage of EL=208 V:
ISC=3ELMVASC−tot (8.17)
ISC=3(208 V)18.94 MVA=52,583 A