Question 9.3: Charge Sharing Consider the idealized cross section of a sh...

Charge Sharing

Consider the idealized cross section of a short-channel transistor shown in the accompanying figure. The maximum depletion width away from the source and drain junctions is x_{dmax},  r_j is the junction radius, and r_2 is the radial distance to the corner of the trapezoid shown in the figure. W is the width of the channel and N_a is the dopant density.

Considering the reduced depletion-region charge that needs to be induced by the gate electrode, derive an approximate expression for the threshold voltage for small values of V_{DS} .

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

For small values of V_{DS} , we consider the charge induced by   V_G to be approximately contained in a volume whose cross section is the trapezoid of width x_{dmax} and length varying from L at the surface to L_1 at the substrate side of the depletion region. The cross-sectional area is shown cross-hatched on the figure. If this charge is called Q_{d1} then

Q_{d1}=qx_{dmax}WN_a\frac{L+L_1}{2}                                  (1)

The charge Q_{d1} in Equation 1 is approximately the depletion-layer charge that must be induced by the gate to bring the channel to the threshold condition. If the channel is long so that the space-charge regions at the source and drain are much smaller than L_1 , then L_1 approaches L. In that case, from Equation 1, Q_{d1} equals Q_d = q x_{dmax} N_a WL , as was assumed in the first-order theory of Sec. 9.1. For shorter channels, L_1 becomes appreciably less than L, and Q_{d1} is therefore less than Q_d as expccted from our qualitative arguments.

For a useful theory, L_1 must be related to the geometry of the MOSFET. This can be done approximately by assuming that when V_G = V_T , the depletion layer is x_{dmax} units wide both in the x-direction (perpendicular to the Si-SiO_2 interface) and along the radius of the diffused source and drain junctions. With this approximation r_2 = r_j + x_{dmax} From the geometry of the structure, we obtain

f\equiv \frac{Q_{d1}}{Q_d} =1-\frac{r_j}{L} \left(\sqrt{1+\frac{2x_{dmax}}{r_j} }-1 \right)                                         (2)

The parameter f is therefore a function of the MOSFET geometry. The expression for the threshold voltage is written directly from Equation 8.3.18:

V_T=V_{FB}+V_C+2\left|\phi _p\right| +\frac{1}{C_{ox}} \sqrt{2\epsilon _sqN_a(2\left|\phi _p\right| +V_C-V_B)}                                                     (8.3.18)

V_T=V_{FB}+2\left|\phi _p\right| +V_S-\frac{fQ_d}{C_{ox}} \\ =V_{FB}+2\left|\phi _p\right| +V_S+\frac{f}{C_{ox}} \sqrt{2\epsilon _sqN_a(2\left|\phi _p\right| +V_S-V_B)}                                                     (3)

Despite the approximate nature of its derivation, Equation 3 is useful in predicting trends in the behavior of V_T for MOSFETs with short channel lengths.

The analysis leading to Equation 3 did not consider the difference between the space-charge dimensions at the source and at the drain and, therefore, represents V_T for small values of V_{DS} .
Because V_{DS} is typically much larger than the source-substrate bias V_{SB} , V_T is sensitive to V_D in short-channel MOSFETs. More elaborate geometric analyses include this effect.

123

Related Answered Questions