Question 15.6: A 35-µF capacitor is connected to a 120-V, 60-Hz line. How m......
A 35-µF capacitor is connected to a 120-V, 60-Hz line. How much current will flow in this circuit?
Step-by-Step
The first step is to compute the capacitive reactance. Recall that the value of C in the formula is given in farads. This must be changed to the capacitive units being used—in this case, microfarads.
X_c=\frac{1}{2 ~\times~ 3.1416 ~\times ~60~ \times~\left(35 ~\times ~10^{-6}\right)}X_c=75.79 ~\Omega
Now that the value of capacitive reactance is known, it can be used like resistance in an Ohm’s law formula. Since capacitive reactance is the current-limiting factor, it will replace the value of R.
I=\frac{E}{X_c}
I=\frac{120}{75.79}
I = 1.58 A
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