Question 15.7: A capacitor is connected into a 480-V, 60-Hz circuit. An amm......

The first step is to compute the value of capacitive reactance. Since capacitive reactance, like resistance, limits current flow, it can be substituted for R in an Ohm’s law formula.

X_C=\frac{E}{I}

 X_C=\frac{480}{2.6}

                                                         X _{ C }=184.61~ \Omega

   Now that the capacitive reactance of the circuit is known, the value of capacitance can be found.

                                             C=\frac{1}{2\pi F X_C}

C=\frac{1}{2~ \times ~3.1416~ \times ~60~ \times ~184.61}

                                           C=\frac{1}{69,596.49}

                                             C = 0.00001437 F = 14.37 µF