What would be the plate area of a 1-F (farad) capacitor if air is used as the dielectric and the plates are separated by a distance of 1 inch?
The first step is to convert the above formula to solve for area.
A=\frac{C ~\times~ 4.45 ~\times ~D}{K}
A=\frac{1,000,000,000,000~ \times ~4.45 ~\times~ 1}{1}
A = 4,450,000,000,000 square inches
A = 1108.5 square miles
Since the basic unit of capacitance is so large, other units such as the microfarad (µF), nanofarad (nF), and picofarad (pF) are generally used.
\begin{aligned}& \mu F =\frac{1}{1,000,000}\left(1 \times 10^{-6}\right) \\& \text { ~~~~~~~~~~of a farad } \\ \\& nF =\frac{1}{1,000,000,000}\left(1 \times 10^{-9}\right)\\ & \text { ~~~~~~~~~~of a farad } \\ \\ & pF =\frac{1}{1,000,000,000,000}\left(1 \times 10^{-12}\right) \\& \text {~~~~~~~~~~ of a farad }\end{aligned}
The picofarad is sometimes referred to as a micro-microfarad and is symbolized by µµF.