A pipe 250 mm dia, 4000 m long with f = 0.021 discharges water from a reservoir at a level 5.2 m below the water reservoir level. Determine the rate of discharge.
The head available should equal the sum of frictional loss and the dynamic head.
Frictional Head = f L u_{m}^{2}/2\mathrm{g} D, Dynamic Head = u_{m}^{2}/2\mathrm{g}
When long pipes are involved, minor losses may often be neglected.
5.2 = [(0.021 × 4000 × u_{m}^{2})/(2 × 9.81 × 0.25)] + [u_{m}^{2} / (2 × 9.81)] \\ = 17.176 u_{m}^{2}
∴ u_{m} = 0.55 m/s.
∴ Flow rate = (π × 0.25²/4) × 0.55 = 0.027 m³/s. or 97.23 m³/hr.