For an 8-PSK system, operating with an information bit rate of 24 kbps, determine (a) baud, (b) minimum bandwidth, and (c) bandwidth efficiency.
a. Baud is determined by substituting into Equation 10:
B=\frac{f_{b}}{N} (10)
baud =\frac{24,000}{3}=8000b. Bandwidth is determined by substituting into Equation 11:
baud =\frac{f_{b}}{N} (11)
B=\frac{24,000}{3}=8000c. Bandwidth efficiency is calculated from Equation 27:
Bη=\frac{\text{transmission bit rate }\,(bps)}{\text{ minimum bandwidth }\,(Hz)} (27)
Bη=\frac{24,000}{8000}\frac{bps}{Hz}= 3 bits per second per cycle of bandwidth