## Chapter 2

## Q. 2.5

## Step-by-Step

## Verified Solution

For a binary data input of Q = 0 and I = 0, the two inputs to the I balanced modulator are -1 and sin ω_{c}t, and the two inputs to the Q balanced modulator are -1 and cos ω_{c}t. Consequently, the outputs are

I balanced modulator = (-1)(sin ω_{c}t) = -1 sin ω_{c}t

Q balanced modulator = (-1)(cos ω_{c}t) = -1 cos ω_{c}t

and the output of the linear summer is

-1 cos ω_{c}t – 1 sin ω_{c}t = 1.414 sin(ω_{c}t – 135°)

For the remaining dibit codes (01, 10, and 11), the procedure is the same. The results are shown in Figure 18a.