If \cos x=-\frac{1}{3} and x lies in Quadrant III, find the values of
(i) \sin \frac{x}{2},\quad (ii) \cos \frac{x}{2} ,\quad (iii) \tan \frac{x}{2}.
Since x lies in Quadrant III, we have
\begin{aligned}\pi<x<\frac{3 \pi}{2} & \Rightarrow \frac{\pi}{2}<\frac{x}{2}<\frac{3 \pi}{4}\\ \\& \Rightarrow \frac{x}{2} \text { lies in Quadrant II } \\ \\& \Rightarrow \sin \frac{x}{2}>0 \text { and } \cos \frac{x}{2}<0 .\end{aligned}(ii) 2 \cos ^{2} \frac{x}{2}=(1+\cos x)=\left(1-\frac{1}{3}\right)=\frac{2}{3} \\ \\\begin{array}{l}\Rightarrow \cos ^{2} \frac{x}{2}=\frac{1}{3} \\ \\\Rightarrow \cos \frac{x}{2}=-\frac{1}{\sqrt{3}}=\frac{-1}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}}=-\frac{\sqrt{3}}{3} .\end{array}
(iii) \tan \frac{x}{2}=\frac{\sin \left(\frac{x}{2}\right)}{\cos \left(\frac{x}{2}\right)}=\left(\frac{\sqrt{6}}{3} \times \frac{3}{-\sqrt{3}}\right)=-\sqrt{2} .