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Question 15.5.4: Prove that 1+cos x/1-cos x=(cosec x+cot x)² ....

Prove that \frac{1+\cos x}{1-\cos x}=(\operatorname{cosec} x+\cot x)^{2} .

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We have

\begin{aligned}\text { LHS } & =\frac{1+\cos x}{1-\cos x} \\  \\& =\frac{2 \cos ^{2}\left(\frac{x}{2}\right)}{2 \sin ^{2}\left(\frac{x}{2}\right)}=\cot ^{2} \frac{x}{2}\left[\begin{array}{c}\because 1+\cos x=2 \cos ^{2}\left(\frac{x}{2}\right), \\  \\1-\cos x=2 \sin ^{2}\left(\frac{x}{2}\right)\end{array}\right]\end{aligned}\\  \\

\begin{aligned}\text { RHS } & =(\operatorname{cosec} x+\cot x)^{2} \\  \\& =\left(\frac{1}{\sin x}+\frac{\cos x}{\sin x}\right)^{2}=\left(\frac{1+\cos x}{\sin x}\right)^{2}\\  \\& =\left\{\frac{2 \cos ^{2}\left(\frac{x}{2}\right)}{2 \sin \left(\frac{x}{2}\right) \cos \left(\frac{x}{2}\right)}\right\}^{2}=\left\{\frac{\cos \left(\frac{x}{2}\right)}{\sin \left(\frac{x}{2}\right)}\right\}^{2}=\cot ^{2} \frac{x}{2} .\end{aligned}\\  \\ \therefore \quad LHS = RHS.

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