Question 18.6: Name the alkane. CH3CHCH2CHCH3 | | CH3 CH3...
Name the alkane.
CH_3\underset{\begin {matrix}| \\ CH_3 \end {matrix}}{CH}CH_2\underset{\begin {matrix}| \\ CH_3 \end {matrix}}{CH}CH_3Step-by-Step
1. The longest continuous carbon chain has five atoms.
Therefore the base name is pentane.
2. This compound has two substituents, both of which are
named methyl.
\begin {matrix} H_3C&-&CH&-&CH_2&-&CH&-&CH_3 \\&&|&&&&| \\ &&CH_3&&&&CH_3 \end {matrix} \\ CH_3\underset{\begin {matrix}| \\ \underset{Methyl}{CH_3} \end {matrix}}{CH}CH_2\underset{\begin {matrix}| \\ \underset{Methyl}{CH_3} \end {matrix}}{CH}{CH_3} \\
3. Since both substituents are equidistant from the ends, it does not matter which end you start numbering from.
\overset{1}{C}H_3\underset{\begin {matrix}| \\ {C}H_3 \end {matrix}}{\overset{2}{C}H}\overset{3}{C}H_2\underset{\begin {matrix}| \\ CH_3 \end {matrix}}{\overset{4}{C}H}\overset{5}{C}H_34. and 5. Since this compound contains two identical sub-stituents, Rule 5 applies and we use the prefix di-.
2,4-dimethylpentane
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