Write structural formulas for all of the isomers of pentyne (C_5H_8).
Pentyne has five carbon atoms with one triple bond between two of them. The possible backbone structures are:
C\equiv C-C-C-C \\ C-C\equiv C-C-C \\ \begin {matrix} C &\equiv &C&-&C&-&C \\ &&&&| \\ &&&&C \end {matrix}Once you have determined all of the unique backbone structures, add hydrogen atoms to give each carbon atom four bonds. Then add hydrogen atoms so that each carbon atom forms four bonds.
HC\equiv C-CH_2-CH_2-CH_3 \\ H_3C-C\equiv C-CH_2-CH_3 \\ \begin {matrix} HC &\equiv &C&-&CH&-&CH_3 \\ &&&&| \\ &&&&H_3C \end {matrix}