Signal energy of a sinc signal
Find the signal energy of x[n] = (1/5)sinc(n/100).
The signal energy of a signal is defined as
E_x=\sum\limits_{n=-\infty }^{\infty }{\left|x[n]\right|^2 } .
But we can avoid doing a complicated infinite summation by using Parseval’s theorem. The DTFT of x[n] can be found by starting with the Fourier pair
sinc(n/w)\xleftrightarrow[]{\mathcal{F} }wrect(wF)*\delta _1(F).
and applying the linearity property to form
(1/5)sinc(n/100)\xleftrightarrow[]{\mathcal{F} }20rect(100F)*\delta _1(F).
Parseval’s theorem is
\sum\limits_{n=-\infty }^{\infty }{\left|x[n]\right|^2 }=\int_{1}^{}{\left|X(F)\right| } ^2 dF.
So the signal energy is
E_x=\int_{1}^{}{\left|20rect(100 F)*\delta _1(F)\right| }^2 dF =\int_{-\infty }^{\infty }{{\left|20rect(100 F)\right| }^2 dF} .
or
E_x=400\int_{-1/200}^{1/200}{dF} =4.