Question 12.2: TRANSISTOR STABILITY The Triquint T1G6000528 GaN HEMT has th...

TRANSISTOR STABILITY

The Triquint T1G6000528 GaN HEMT has the following scattering parameters at 1.9 GHz(Z_{0} = 50 Ω):

S_{11} = 0.869∠−159°

 

S_{12} = 0.031∠−9°,

 

S_{21} = 4.250∠61°,

 

S_{22} = 0.507∠−117°

Determine the stability of this transistor by using the K − Δ test and the µ-test,and plot the stability circles on a Smith chart.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

From (12.28) and (12.29) we compute K and |Δ| as

\left|\Delta \right| =\left|S_{11}S_{22}-S_{12}S_{21}\right| =0.336

 

k =\frac{1-\left|S_{11}\right|^{2} -\left|S_{22}\right|^{2}+\left|\Delta \right|^{2} }{2\left|S_{12}S_{21}\right| } =0.383

Thus we have |Δ| < 1 but not K > 1, so the unconditional stability criteria of (12.28)–(12.29) are not satisfied, and the device is potentially unstable. The stability of this device can also be evaluated using the µ-test, for which (12.30) gives µ = 0.678, again indicating potential instability.

\mu =\frac{1-\left|S_{11}\right|^{2}}{\left|S_{22}-\Delta S_{11}^*\right| +\left|S_{12}S_{21}\right| } =0.383>1                (12.30)

The centers and radii of the stability circles are given by (12.25) and (12.26):

C_{L}=\frac{(S_{22}-\Delta S_{11}^{*})^{*}}{\left|S_{22}\right|^{2}-\left|\Delta \right|^{2} } =1.59\angle 132^{\circ }

 

R_{L}=\frac{\left|S_{12} S_{21}\right| }{\left|S_{22}\right|^{2}-\left|\Delta \right|^{2} } =0.915

 

C_{S}=\frac{(S_{11}-\Delta S_{22}^{*})^{*}}{\left|S_{11}\right|^{2}-\left|\Delta \right| ^{3} } =1.09\angle 162^{\circ }

 

R_{S}=\frac{\left|S_{12}S_{21}\right| }{\left|S_{11}\right|^{2}-\left|\Delta \right|^{2} } =0.205

These data can be used to plot the input and output stability circles, as shown in Figure 12.6. Since |S_{11}| < 1 and |S_{22}| < 1, the central part of the Smith chart represents the stable operating region for Γ_{S} and Γ_{L}. The unstable regions are shaded.

1

Related Answered Questions