Calculate the freezing point of a 2.5 m aqueous sucrose solution.
GIVEN: 2.5 m solution
FIND: \Delta T_f
\Delta T_f= m \times K_f \\ =2.5 \frac{\cancel{mol solute}}{\cancel{kg solvent}} \times 1.86 \frac{°C \cancel{ kg solvent}}{\cancel{mol solute}} \\ = 4.7 °CFreezing point = 0.00 °C – 4.7 °C
= -4.7 °C