Question 13.14: How much KCl in grams is contained in 0.488 L of 1.25 M KCl ......
How much KCl in grams is contained in 0.488 L of 1.25 M KCl solution?
Step-by-Step
GIVEN: 1.25 M KCI
0.488 L solution
FIND: g KCl
RELATIONSHIPS USED
\frac{1.25 mol KCl}{L solution}(given molarity, written as a fraction)
1 mol = 74.55 g (molar mass KCl)
0.488 \cancel{L solution} \times \frac{1.25 \cancel{mol KCl}}{\cancel{L solution}}\times \frac{74.55 g KCl}{\cancel{mol KCl}} = 45.5 g KCl
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