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Question 13.8: Calculate the molality of a solution containing 17.2 g of et......

Calculate the molality of a solution containing 17.2 g of ethylene glycol (C_2H_6O_2) dissolved in 0.500 kg of water.

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GIVEN: 17.2 g C_2H_6O_2
0.500 kg H_2O
FIND: molality (m)

\mathrm{mol\,C_{2}H_{6}O_{2}=17.2\cancel{\,g\,C_{2}H_{6}O_{2}}\times\frac{1\,\mathrm{mol\,C_{2}H_{6}O_{2}}}{62.08  \cancel{g  \mathrm{C}_{2}H_{6}O_{2}}}} \\ = 0.27\underline{7}1\;mol\;C_2H_6O_2 

Molality (m)= \frac{ \mathrm{Moles \; solute}}{\mathrm{Kilograms \; solvent}} \\ =  \frac{0.2771  mol  C_2H_6O_2}{0.500  kg  H_2O} \\ = 0.554  m

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