How much of an 8.0 M HCl solution should be used to make 0.400 L of a 2.7 M HCl solution?
GIVEN:
M_1 = 8.0 M
M_2= 2.7 M
V_2= 0.400 L
FIND: V_1
M_1V_1=M_2V_2 \\ V_{1}={\frac{M_{2}V_{2}}{M_{1}}} \\ =\frac{2.7 \cancel{\frac{mol}{L}} \times 0.400 L}{0.8 \cancel{\frac{mol}{L}}} \\ =0.14 L