Question 13.17: Calculate the molality of a solution containing 0.183 mol of......
Calculate the molality of a solution containing 0.183 mol of sucrose dissolved in 1.10 kg of water.
Step-by-Step
GIVEN: 0.183 mol of sucrose
1.10 kg H_2O
FIND: molality (m)
Molality (m)=\frac{\mathrm{Moles \;solute}}{\mathrm{Kilograms \; solvent}}
Molality (m)= \frac{0.183 mol sucrose}{1.10 kg H_2O} \\ = 0.166 m
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