Question 11.5: A 4.8-L sample of helium gas contains 0.22 mol of helium. Ho......
A 4.8-L sample of helium gas contains 0.22 mol of helium. How many additional moles of helium gas must be added to the sample to obtain a volume of 6.4 L? Assume constant temperature and pressure.
Step-by-Step
GIVEN:
V_1 = 4.8 L
n_1 = 0.22 mol
V_2 = 6.4 L
FIND: n_2
RELATIONSHIPS USED
{\frac{V_{1}}{n_{1}}}\,=\,{\frac{V_{2}}{n_{2}}} (Avogadro’s law, presented in this section)
{\frac{V_{1}}{n_{1}}}\,=\,{\frac{V_{2}}{n_{2}}} \\ n_{2}={\frac{V_{2}}{V_{1}}}\;n_{1} \\ ={\frac{6.4\,{\mathrm{\cancel{L}}}}{4.8\,{\mathrm{\cancel{L}}}}}0.22\,{\mathrm{mol}}= 0.29 mol
mol to add = 0.29 – 0.22 = 0.07 mol
Related Answered Questions
Question: 11.15
Verified Answer:
GIVEN:
P_1 = 855 mm Hg
V_1[/...
Question: 11.16
Verified Answer:
GIVEN:
n = 1.2 mol
V = 28.2 L
T = 334 K
FIND: P
RE...
Question: 11.14
Verified Answer:
GIVEN:
P_1 = 3.2 atm
V_1[/la...
Question: 11.13
Verified Answer:
GIVEN: 18.4 in. Hg
FIND: torr
RELATIONSHIPS USED
1...
Question: 11.12
Verified Answer:
GIVEN:1.24 L H_2
FIND: g H_2...
Question: 11.11
Verified Answer:
GIVEN:
294 g KClO_3
P = 755 mm Hg (...
Question: 11.8
Verified Answer:
GIVEN:
m = 0.311 g
V = 0.225 L
t = 55 °C
P = 886 m...
Question: 11.7
Verified Answer:
GIVEN:
P = 24.2 psi
V = 3.2 L
t = 25 °C
FIND: n
RE...
Question: 11.6
Verified Answer:
GIVEN:
n = 0.845 mol
P = 1.37 atm
T = 315 K
FIND: ...
Question: 11.4
Verified Answer:
GIVEN:
P_1 = 735 mm Hg
t_1[/...