Question 11.16: Calculate the pressure exerted by 1.2 mol of gas in a volume......
Calculate the pressure exerted by 1.2 mol of gas in a volume of 28.2 L and at a temperature of 334 K.
Step-by-Step
GIVEN:
n = 1.2 mol
V = 28.2 L
T = 334 K
FIND: P
RELATIONSHIPS USED
PV = nRT (Ideal gas law, Section 11.8)
PV = nRT
P =\frac{nRT}{V} \\ =\frac{1.2 \cancel{mol}\times 0.0821 \frac{\cancel{L} \cdot atm}{\cancel{mol} \cdot \cancel{K}}\times 334 \cancel{K}}{28.2 \cancel{L}} \\ =1.2 atmThe units (atm) are correct units for pressure. The value of the answer is a bit more difficult to judge. However, knowing that at standard temperature and pressure (T = 0 °C or 273.15 K and P = 1 atm), 1 mol of gas occupies 22.4 L, we can see that the answer is reasonable because we have a bit more than one mole of a gas at a temperature not too far from standard temperature. The volume of the gas is a bit higher than 22.4 L; therefore we might expect the pressure to be a bit higher than 1 atm.
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