Question 11.12: How many grams of water form when 1.24 L of H2 gas at STP co......
How many grams of water form when 1.24 L of H_2 gas at STP completely reacts with O_2?
2 H_2(g) + O_2(g) → 2 H_2O(g)
Step-by-Step
GIVEN:1.24 L H_2
FIND: g H_2O
RELATIONSHIPS USED
1 mol = 22.4 L (molar volume at STP, presented in this section)
2 mol H_2 : 2 mol H_2O (from balanced equation given in problem)
18.02 g H_2O = 1 mol H_2O(molar mass of H_2O)
1.24 \cancel{L H_2}\times \frac{1 \cancel{mol H_2}}{22.4 \cancel{L H_2}}\times \frac{2 \cancel{mol H_2O}}{2 \cancel{ mol H_2}}\times \frac{18.02 g H_2O}{1 \cancel{mol H_2O}}=0.998 g H_2O
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