Question 11.6: Calculate the volume occupied by 0.845 mol of nitrogen gas a......
Calculate the volume occupied by 0.845 mol of nitrogen gas at a pressure of 1.37 atm and a temperature of 315 K.
Step-by-Step
GIVEN:
n = 0.845 mol
P = 1.37 atm
T = 315 K
FIND: V
RELATIONSHIPS USED
PV = nRT (Ideal gas law, presented in this section)
PV = nRT
V\,=\,{\frac{n R T}{P}} \\ V={\frac{0.845\;\mathrm{\cancel{mol}}\times0.0821\;{\frac{L\cdot{\mathrm{\cancel{atm}}}}{\mathrm{\cancel{mol}}\times \cancel{K}}}\;\cdot\;315\;\mathrm{\cancel{K}}}{1.37\;\mathrm{\cancel{atm}}}}=16.0\;\mathrm{L}The answer has the correct units for volume, liters. The value of the answer is a bit more difficult to judge. However, at standard temperature and pressure (T = 0 °C or 273.15 K and P = 1 atm), 1 mol gas occupies 22.4 L (see Section 11.10). Therefore our answer of 16.0 L seems reasonable for the volume of 0.85 mol of gas under conditions that are not too far from standard temperature and pressure.
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