A gas has a volume of 5.7 L at a pressure of 3.2 atm. What is its volume at 4.7 atm? (Assume constant temperature.)
GIVEN:
P_1 = 3.2 atm
V_1 = 5.7 L
P_2 = 4.7 atm
FIND: V_2
RELATIONSHIPS USED
P_1V_1 = P_2V_2 (Boyle’s law, Section11.4)
P_1V_1 = P_2V_2 torr
V_2 =\frac{P_1}{P_2} V_1\\=\frac{3.2 \cancel{atm}}{4.7 \cancel{atm}} 5.7 L\\= 3.9 LThe units (L) are correct. The value is reasonable because as the pressure increases the volume should decrease.